Problem of the Day
A new programming or logic puzzle every Mon-Fri

Comments:

• Johnathan - 10 years, 4 months ago

  import time
  
  def cronjobtypefunction(seconds):
      start = time.clock()
  
      while seconds > time.clock() - start:
          print time.clock()
  
  q = raw_input('How do you want the cron job type function to run? Enter s for seconds or m for minutes: ')
  if q == 'm' or q == 'M':
      t = float(raw_input('How many minutes do you want to run the cron job type function?'))
      t = t * 60
  elif q == 's' or q == 'S':
      t = float(raw_input('How many seconds do you want to run the cron job type function?'))
  
  cronjobtypefunction(t)
  

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• Johnathan - 10 years, 4 months ago

  Oops...forgot to do hours and days. Oh well, I made my submission. Guess I lose out on bonus.

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• David - 10 years, 4 months ago

  Why not use time.sleep() ? Your while loop is actively counting instead of suspending the execution thread.

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• Johnathan - 10 years, 4 months ago

  I guess I misunderstood the concept.

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• David - 10 years, 4 months ago

  S'all good. This website is (potentially) a great place to learn this kind of stuff, so long as other commenters actually say something. Lots of this code will end up being quick and dirty, but that can be a good way to catch some of one's ingrained habits.

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• Johnathan - 10 years, 4 months ago

  100% honest I love feedback. If you want to take the time to read over my stuff and give suggestions I would really like it.

  Don't want you to think I'm taking it the wrong way. I know some things, but in the big picture I'm still fairly new.

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• David - 10 years, 4 months ago

  I added a randomized exit condition so it does not require a forced quit.

  import time
  import random
  
  def checkOnExitCondition():
      print "This is where one could check for some kind of exit logic"
      retVal = random.uniform(0,1) < 0.25
      return retVal
  
  def cronJob():
      print "This print is a placeholder for a real cron job"
  
  def cronFunc(sec, mins = 0, hr = 0, day = 0):
      exitCondition = 0
      timetosleep = 60*(60*(24*day + hr) + mins) + sec
      while(not exitCondition):
          time.sleep(timetosleep)
          cronJob()
          exitCondition = checkOnExitCondition()
  
  print "Start:"
  cronFunc(1)
  print "Good thing it randomly finished"
  

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• Nick Krichevsky - 10 years, 4 months ago

  I decided to do it two ways because I am not sure which would be better from a system standpooint.

  Solution 1, time.sleep()

  from time import sleep
  def function():
      print "I'm running!"
  print "Enter how long until this function runs. Days,Hours,Mins,Seconds"
  q = raw_input()
  times = q.split(',')
  seconds = 0
  div = 86400
  for item,i in zip(times,range(len(times))):
      seconds+=int(item)*div
      if i==0:
          div/=24
      else:
          div/=60
  while True:
      sleep(seconds)
      function()
  

  Solution 2, Custom timer

  from threading import Event,_Timer
  class CronTimer(_Timer):
      def __init__(self,interval,function,*args,**kwargs):
          _Timer.__init__(self,interval,function,args,kwargs)
          self.interval = interval
          self.function = function
          self.args = args
          self.kwargs = kwargs
          self.finished = Event()
      def run(self):
          while True:
              super(CronTimer,self).run()
              self.finished = Event()
  
              print 'hm'
  def function():
      print "I'm running!"
  
  print "Enter how long until this function runs. Days,Hours,Mins,Seconds"
  q = raw_input()
  times = q.split(',')
  seconds = 0
  div = 86400
  for item,i in zip(times,range(len(times))):
      seconds+=int(item)*div
      if i==0:
          div/=24
      else:
          div/=60
  
  c = CronTimer(seconds,function)
  c.start()
  

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