Problem of the Day
A new programming or logic puzzle every Mon-Fri

Comments:

• Anonymous - 10 years, 1 month ago

  def largest_difference(lst):
      return max(abs(a-b) for a, b in zip(lst, lst[1:]))
  

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• Anon - 10 years, 1 month ago

  Java:

    public int highestDiff (int[] array) {
      int highest = 0;
      for (int i : array) {
        if (i > highest) {
          highest = i;
        }
      }
  
      int lowest = highest;
      for (int j : array) {
        if (j < lowest) {
          lowest = j;
        }
      }
  
      return highest - lowest;
    }
  

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• Anonymous - 10 years, 1 month ago

  C#

      public static int LargestDifference(int[] arr)
      {
          int difference = 0;
          for(int i = 0; i < arr.Length -1; i++)
              difference = Math.Abs(arr[i] - arr[i + 1]) > difference ? Math.Abs(arr[i] - arr[i + 1]) : difference;
          return difference;
      }
  

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• Jordan - 10 years, 1 month ago

  Here's the javascript version of this!

  var array = [4, 10, 20, 30, 50, 67, 4, 20]; var len = array.length; var high = 0;

  for (i = 0; i < len || function(){ alert(high); return false;}(); i += 2){

  largest_diff(array[i], array[i+1]);
  

  }

  function largest_diff(x, y){

  var sum = x - y;
  
  var absolute = Math.abs(sum);
  
  if(absolute > high){
         high = absolute;
  }
  
  return high;
  

  }

  jsfiddle here:

  http://jsfiddle.net/rryw8abo/9/

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• Jordan - 10 years, 1 month ago

  Javascript:

  http://jsfiddle.net/rryw8abo/10/

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• Driphter - 10 years, 1 month ago

  Clojure!

  (defn max-adj-diff [s]
    (->> (map - s (next s))
         (map #(Math/abs %))
         (apply max)))
  

  C#!

  int MaxAdjacentDifference(int[] arr)
  {
      return arr.Zip(arr.Skip(1), (x, y) => x - y)
                .Max(x => Math.Abs(x));
  }
  

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• Anonymous - 10 years, 1 month ago

  Cool did not know about the zip method in c#

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• Nick - 10 years, 1 month ago

  Javascript:

  var difference = function(array) {
      array = array || [];
      return Math.max.apply(null, array.map(function(el, idx) {
          return Math.abs((el - array[idx + 1])) || 0;
      }));
  }
  

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