Problem of the Day
A new programming or logic puzzle every Mon-Fri

Pizza Calculator

The final day of June. We've come so far!

Today's problem will prove super useful when ordering pizza. Write a function that takes in an int (diameter of a circle) and a float (price) and determine the cost per unit of area (price/area). Next time you order a pizza you can plug in the sizes and prices and determine which is the better buy.

Permalink: http://problemotd.com/problem/pizza-calculator/

Comments:

  • Emre Ozdemir - 10 years, 5 months ago

    #include <iostream>                               //Solution in C++
#define PI 3.14159265359                   //To see which pizza is better, you need to try more than once in the same window 
using namespace std;

void checkCostpArea(int varDia, float varPrice){
    double area = PI * varDia * varDia; 
    cout<<endl<<"You will pay "<< varPrice << "$ for "<< area <<" cm^2 pizza."<<endl;
    cout<<"And the Price/Area ratio is: "<< varPrice/area<<endl;
};

int main (){
    int diameter;
    double loop=1.0;
    float price;

    while(loop!=0){
        for(int i=1;i<=30;i++)      //per try divider
            cout<<"-";
        puts("\n");
    cout<<"Enter the pizza diameter: "; //this will be in centimeters
    cin>>diameter;

    cout<<"Enter the price: ";  //this will be in dollars
    cin>>price;

    checkCostpArea(diameter,price);

    cout<<endl<<"Type 0 to exit, any number to go again.";
    cin>>loop;
    }
    return 0;
}

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  • Anonymous - 10 years, 5 months ago

    #python 2.7
size = float(raw_input("What's the diameter of the pizza?> "))
price = float(raw_input("How much is the pizza?> $"))

square_inches = 3.14159 * (price/2.0)**(2.0)

print "Price per square inch = $%f" % (price/square_inches)

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  • Anonymous - 10 years, 5 months ago

    Oops. That should be: square_inches = 3.14159 * (size/2.0)**(2.0)

    size not price :/

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  • Anonymous - 10 years, 5 months ago

    Haskell solution

    main :: Int -> Float -> String
main i f = pizza (toEnum (quot i 2)) f

pizza :: Float -> Float -> String
pizza z s = "Price per cm^2: " ++ show price
    where
        a = z * z * pi
        price = s / a

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  • bumbleguppy - 10 years, 5 months ago

    javascript

      function pizzaValue(diameter, price)
  {
        return '$' + (price / (((diameter / 2) ^ 2) * Math.PI)).toFixed(2).toString() + ' per square inch';
  }

  console.log(pizzaValue(10, 12.99));

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