Problem of the Day
A new programming or logic puzzle every Mon-Fri

Comments:

• Alex - 10 years, 5 months ago

  probably not the most efficient (nor the prettiest) way of doing it but here's my attempt with JS:

  var input = "30c to k";
  
  for (var i = 0; i < input.length; i++) {
      if (input.charAt(i) == "c" || input.charAt(i) == "f" || input.charAt(i) == "k") {
          convert(input.substring(0, input.indexOf(input.charAt(i))), input.charAt(i), input.charAt(input.length - 1));
          break;
      }
  }
  
  function convert(temp, from, to) {
      switch (from) {
          case "c":
              if (to === "k") {
                  console.log(273.15 + parseInt(temp, 10));
                  break;
              } else if (to === "f") {
                  console.log(9 / 5 * parseInt(temp, 10) + 32);
                  break;
              } else {
                  console.log("can't do that");
                  break;
              }
          case "k":
              if (to === "f") {
                  console.log((parseInt(temp, 10) - 273.15) * 1.8 + 32);
                  break;
              } else if (to === "c") {
                  console.log(parseInt(temp, 10) - 273.15);
                  break;
              } else {
                  console.log("can't do that");
                  break;
              }
          case "f":
              if (to === "c") {
                  console.log(5 / 9 * (parseInt(temp, 10) - 32));
                  break;
              } else if (to === "k") {
                  console.log((parseInt(temp, 10) - 32) / 1.8 + 273.15);
                  break;
              } else {
                  console.log("can't do that");
                  break;
              }
      }
  }
  

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• Mihmal - 10 years, 5 months ago

  I think that using 6 separate functions is better

  def celsius_to_kelvin(t):
    if t < -273:
      raise ArgumentError
    else: return t+273
  
  def kelvin_to_celsius(t):
    return t+273
  
  def celsius_to_fahrenheit(t):
    return t*9/5.+32
  
  def fahrenheit_to_celsius(t):
    return (t-32)*5/9. 
  
  def kelvin_to_farenheight(t):
    return (t-273.15)*1.8 + 32.00
  
  def farenheight_to_kelvin(t):
    return (t-32)*5/9. + 273.15
  

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