Problem of the Day
A new programming or logic puzzle every Mon-Fri

Building off of yesterday's problem let's create a binary to ASCII converter. The string "0101100101101111011101010010000001110011011011110110110001110110011001010110010000100000011010010111010000100001" should map to "You solved it!". If it helps, you only need to account for characters 32-126 from the ASCII table.

As a bonus create a way to go from ASCII to binary.

Comments:

• Anonymous - 10 years, 5 months ago

  #!/usr/bin/env python2
  bits = '0101100101101111011101010010000001110011011011110110110001110110011001010110010000100000011010010111010000100001'
  print ''.join(chr(int(''.join(map(str,map(int, ''.join([c for c in bits ]))[i:i+8])),2)) for i in range(0,len(map(int, ''.join([c for c in bits ]))),8))
  

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• pyrohaze - 10 years, 5 months ago

  Python solution

  binary=raw_input("input?\n")
  binary_sep = [binary[8*i:8*(i+1)] for i in xrange(len(binary)//8)]
  ints = [int(x, 2) for x in binary_sep]
  chars = [chr(x) for x in ints]
  print ''.join(chars)
  

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• Anonymous - 10 years, 5 months ago

  Clojure:

  (defn binToText [bin]
    (if (< 8 (count bin))
        (str (char (Integer/parseInt (subs bin 0 8) 2)) 
             (binToText (subs bin 8)))))
  

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• Anonymous - 10 years, 5 months ago

  #python 2.7
  a = raw_input("Enter a string> ")
  b = ""
  for letters in a:
      b = b + str(bin(ord(letters))[2:9])
  
  print b
  

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• Anonymous - 10 years, 5 months ago

  That's ASCII to Binary. People already solved the other way.

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• bumbleguppy - 10 years, 5 months ago

  javascript

  function binary2ascii(msg){
      var returnValue = '';
      var bytePad = ''
      var i;
      var len = msg.length;
      if(msg.replace(/[01]*/g,'').length){
          for(i = 0; i < len; i++){
              bytePad = msg.charCodeAt(i).toString(2);
              if(bytePad.length < 8){
                  bytePad = ('00000000' + bytePad).substr(bytePad.length); 
              }
              returnValue += bytePad;
          }
      }else{
          for(i = 0;i < len; i+=8){
              returnValue += String.fromCharCode(parseInt(msg.substring(i, (i + 8)), 2));
          }
      }
      return returnValue;
  }
  
  console.log(binary2ascii('0101100101101111011101010010000001110011011011110110110001110110011001010110010000100000011010010111010000100001'));
  
  console.log(binary2ascii('You solved it!'));
  

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• Anonymous - 10 years, 5 months ago

  #python 2.7
  
  def bin_to_ascii(binarynumber):
      i = 0
      output = ""
      while i < len(binarynumber):
          output = output + chr(int("0b" + binarynumber[i: i+8], 2))
          i = i + 8
      return output
  
  def ascii_to_bin(script):
      ascii = ""
      for letter in script:
          ascii = ascii + ("{0:08d}".format(int(bin(ord(letter))[2:])))
  
      return ascii
  

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