Problem of the Day
A new programming or logic puzzle every Mon-Fri

Welcome to the first day of October! To honor the first day of October we'll be building a converter from octal to decimal. Your converter must have some sort of validation. For instance, 39 is not a valid octal number where as 31 is. If your function takes in 31 it should output 25.

Comments:

• nebyark - 10 years, 2 months ago

  #converts octal to decimal
  str = '8'
  while(int(str[len(str)-1])>7):
      str = raw_input("input valid octal number: ")
  sum = 0
  for i in range(0,len(str)):
      sum += int(str[i])*(8**(len(str)-(i+1)))
  print sum
  

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• xConorrr - 10 years, 2 months ago

       do{
              try{
              System.out.print("\nEnter an octal number: ");
              Integer num = Integer.parseInt(in.nextLine(), 8);
              System.out.println("Decimal form: " +num);
              break;
              }catch(Exception e){
                  System.out.println("You must enter a valid octal number!");
              }
          }while(true);
  

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