Problem of the Day
A new programming or logic puzzle every Mon-Fri

The final day of June. We've come so far!

Today's problem will prove super useful when ordering pizza. Write a function that takes in an int (diameter of a circle) and a float (price) and determine the cost per unit of area (price/area). Next time you order a pizza you can plug in the sizes and prices and determine which is the better buy.

Comments:

• Emre Ozdemir - 10 years, 6 months ago

  #include <iostream>                               //Solution in C++
  #define PI 3.14159265359                   //To see which pizza is better, you need to try more than once in the same window 
  using namespace std;
  
  void checkCostpArea(int varDia, float varPrice){
      double area = PI * varDia * varDia; 
      cout<<endl<<"You will pay "<< varPrice << "$ for "<< area <<" cm^2 pizza."<<endl;
      cout<<"And the Price/Area ratio is: "<< varPrice/area<<endl;
  };
  
  int main (){
      int diameter;
      double loop=1.0;
      float price;
  
      while(loop!=0){
          for(int i=1;i<=30;i++)      //per try divider
              cout<<"-";
          puts("\n");
      cout<<"Enter the pizza diameter: "; //this will be in centimeters
      cin>>diameter;
  
      cout<<"Enter the price: ";  //this will be in dollars
      cin>>price;
  
      checkCostpArea(diameter,price);
  
      cout<<endl<<"Type 0 to exit, any number to go again.";
      cin>>loop;
      }
      return 0;
  }
  

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• Anonymous - 10 years, 6 months ago

  #python 2.7
  size = float(raw_input("What's the diameter of the pizza?> "))
  price = float(raw_input("How much is the pizza?> $"))
  
  square_inches = 3.14159 * (price/2.0)**(2.0)
  
  print "Price per square inch = $%f" % (price/square_inches)
  

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• Anonymous - 10 years, 6 months ago

  Oops. That should be: square_inches = 3.14159 * (size/2.0)**(2.0)

  size not price :/

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• Anonymous - 10 years, 5 months ago

  Haskell solution

  main :: Int -> Float -> String
  main i f = pizza (toEnum (quot i 2)) f
  
  pizza :: Float -> Float -> String
  pizza z s = "Price per cm^2: " ++ show price
      where
          a = z * z * pi
          price = s / a
  

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• bumbleguppy - 10 years, 5 months ago

  javascript

    function pizzaValue(diameter, price)
    {
          return '$' + (price / (((diameter / 2) ^ 2) * Math.PI)).toFixed(2).toString() + ' per square inch';
    }
  
    console.log(pizzaValue(10, 12.99));
  

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