Problem of the Day
A new programming or logic puzzle every Mon-Fri

In honor of the 100th problem of the day today's problem will be to print out the numbers 1-100 and 100-1. To be clear you must print out each number 1-100 and then 100-1. Try to optimize for the number of characters used. Fewest number of characters wins!

Comments:

• Lasharn - 10 years, 9 months ago

  This answer is kinda cheaty since it's not a programming language so to speak but on MATLAB just go: disp(1:100); disp(100:-1:1);

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• Anonymous - 10 years, 9 months ago

  On shell I can just do

  seq 1 100;seq 100 -1 1

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• Anonymous - 10 years, 9 months ago

  haskell :

  show([1..100]++[100,99..1])
  

  or print instead of show, but show is one char shorter :D maybe i get something better, but i dunno

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• Anonymous - 10 years, 9 months ago

  It took longer in C++ but still, looks clean.

  #include <iostream>
  using namespace std;
  
  int main (){
      int x = 0; //starting integer x
      int y = 100; //ending integer y
  
      for(int i = x; i <= y;i++)
          cout << i << " ";       //print the integer
  
      swap(x,y); puts("\n");      //swap starting and ending integer - Put space between series
  
      for(int i = x; i >= y;i--)
          cout << i << " ";       //print the integer
  
      getchar();
      getchar();
      return 0;
  };
  

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• Anonymous - 10 years, 9 months ago

  C#

  using System;
  using System.Linq;
  
  class Program
  {
      static void Main(string[] args)
      {
          var r = Enumerable.Range(1, 100);
          Console.WriteLine(String.Join(" ", r.ToArray()) + " " + String.Join(" ", r.OrderByDescending(x => x).ToArray()));
          Console.ReadLine();
      }
  }
  

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• Anonymous - 10 years, 9 months ago

  was able to make it a bit smaller

  using System;
  using System.Linq;
  
  class Program
  {
      static void Main(string[] args)
      {
          var r = Enumerable.Range(1, 100).ToArray();
          Console.Write(String.Join(" ", r) + " " + String.Join(" ", r.Reverse()));
          Console.ReadLine();
      }
  }
  

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• James - 10 years, 9 months ago

  Compile with 'gcc -std=99'

  #include<stdio.h>    
  main(){for(int i=0;i<202;i++) printf("%d\n",i<101?i:201-i);}
  

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• Anonymous - 10 years, 9 months ago

  You can still do it C90 as

  #include<stdio.h>
  main(){int i=0;for(;i<202;i++)printf("%d\n",i<101?i:201-i);}

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• Anonymous - 10 years, 9 months ago

  In Ruby:

  (1..100).each {|n| puts n}  
  100.step(0,-1) {|n| puts n}
  

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• Nick Krichevsky - 10 years, 9 months ago

  Python print range(101),range(101)[::1]

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