Problem of the Day
A new programming or logic puzzle every Mon-Fri

Your goal is to write a function that converts the time something is scheduled to happen in to a unix time stamp. The format you receive is shown below:

• 1d 6h
• 10h 14m
• 7m 8s
• 32s

Thus, if your input was "7m 8s" you'd add 7 minutes and 8 seconds to the current unix time stamp and return that value.

Comments:

• Keemo - 10 years, 5 months ago

  import time
  
  def parseTime(tString):
      if tString[-1] is 'h':
          return int(tString[:-1]) * 60 * 60
      elif tString[-1] is 'm':
          return int(tString[:-1]) * 60
      elif tString[-1] is 's':
          return int(tString[:-1])
      return 0
  
  ti = int(round(time.time()))
  
  usertime = raw_input()
  splits = usertime.split(' ')
  for item in splits:
      ti = ti + parseTime(item)
  print 'result: ' + str(ti)
  

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• Max Burstein - 10 years, 5 months ago

  That was quick. Nice job!

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• Nick Krichevsky - 10 years, 5 months ago

  public class Main {
      public static void main(String[] args){
          String s = "1d 23m";
          String[] sections = s.split(" ");
          long time = System.currentTimeMillis();
          for (String section : sections){
              char unit = section.charAt(section.length()-1);
              int num = Integer.valueOf(section.substring(0, section.length()-1));
              int millis = 0;
              if (unit=='d')
                  millis= num*24*60*60*1000;
              else if (unit=='h')
                  millis = num*60*60*1000;
              else if (unit=='m')
                  millis = num*60*1000;
              else if (unit=='s')
                  millis = num*1000;
              else{
                  System.out.println("Invalid input!");
                  System.exit(0);
              }
              time+=millis;
          }
          System.out.println(time);
      }
  }
  

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